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Oracle 1Z0-007 Exam Syllabus Topics:

Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Evaluate the SQL statement:
SELECT ROUND(45.953, -1), TRUNC(45.936, 2)
FROM dual;
Which values are displayed?

A) 45.95 and 45.93
B) 46 and 45
C) 45 and 45.93
D) 50 and 45.9
E) 46 and 45.93
F) 50 and 45.93

2. You need to write a SQL statement that returns employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
Which statement accomplishes this task?

A) SELECT emp_name, sal, dept_id, maxsal FROM employees, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) WHERE a.sal < maxsal;
B) SELECT a.emp_name, a.sal, b.dept_id, MAX(sal) FROM employees a, departments b WHERE a.dept_id = b.dept_id AND a.sal < MAX(sal) GROUP BY b.dept_id;
C) SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a, (SELECT dept_id, MAX(sal) maxsal FROM employees GROUP BY dept_id) b WHERE a.dept_id = b.dept_id AND a.sal < b.maxsal;
D) SELECT a.emp_name, a.sal, a.dept_id, b.maxsal FROM employees a WHERE a.sal < (SELECT MAX(sal) maxsal FROM employees b GROUP BY dept_id);

3. Which SQL statement displays the date March 19, 2001 in a format that appears as "Nineteenth of March 2001 12:00:00 AM"?

A) SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY'), 'Ddspth "of" Month YYYY fmHH:MI:SS AM') NEW_DATE FROM dual;
B) SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY'), 'fmDdspth "of" Month YYYY HH:MI:SS AM') NEW_DATE FROM dual;
C) SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY'), 'fmDdspth "of" Month YYYY fmHH:MI:SS AM') NEW_DATE FROM dual;
D) SELECT TO_CHAR(TO_DATE('19-Mar-2001', 'DD-Mon-YYYY), 'fmDdspth "of" Month YYYYfmtHH:HI:SS AM') NEW_DATE FROM dual;

4. Examine the data in the EMPLOYEES and DEPARTMENTS tables.

You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?

A) SELECT last_name, department_name FROM employees(+) e JOIN departments d ON (e.department_id = d.department_id);
B) SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
C) SELECT last_name, department_name FROM employees , departments(+);
D) SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
E) SELECT last_name, department_name FROM employees JOIN departments (+);
F) SELECT last_name, department_name FROM employees(+) , departments ON (e.department_id = d.department_id);

5. Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables.

For which situation would you use a nonequijoin query?

A) To find the tax percentage for each of the employees.
B) To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
C) To find the number of employees working for the Administrative department and earning less then 4000.
D) To list the name, job id, and manager name for all the employees.
E) To find the name, salary, and department name of employees who are not working with Smith.

Solutions: