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Oracle 1Z0-501 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Topic 1: Concurrency | - Threads
|
| Topic 2: Java Language Fundamentals | - Language Basics
|
| Topic 3: Core Java APIs | - Collections and Utilities
|
| Topic 4: Exception Handling | - Exceptions
|
| Topic 5: Input and Output | - I/O APIs
|
| Topic 6: Object-Oriented Programming | - Classes and Objects
|
Oracle Java Certified Programmer Sample Questions:
1. CORRECT TEXT
Given:
5. String foo = "base";
6. foo.substring(0,3);
7. foo.concat("ket")
8. Type the value of foo at line 8.
2. Given:
1 . public abstract class Test {
2 . public abstract void methodA();
3 .
4 . public abstract void methodB()
5 . {
6 . System.out.printIn("Hello");
7 .}
8 . }
Which three changes (made independently) allow the code to compile? (Choose Three)
A) Remove the abstract qualifier from the declaration of methodA.
B) Remove methodB in its entirely and change class o interface in line 1.
C) Add a method body to methodA.
D) Replace lines 5-7 with a semicolon (".")
E) Remove the abstract qualifier from the declaration of methodB.
F) Remove the abstract qualifier from the declaration of Test.
3. Given:
1 3. public class Foo {
1 4. public static void main (String [] args){
1 5.StringBuffer a = new StringBuffer ("A");
1 6.StringBuffer b = new StringBuffer ("B");
1 7.operate (a,b);
1 8.system.out.printIn{a + "," +b};
1 9. )
2 0. static void operate (StringBuffer x, StringBuffer y){
2 1.y.append {x};
2 2.y = x;
2 3.)
2 4. }
What is the result?
A) The code does not compile because "+" cannot be overloaded for stringBuffer.
B) The code compiles and prints "AB, AB".
C) The code compiles and prints "BA, BA".
D) The code compiles and prints "AB, B".
E) The code compiles and prints "A, BA".
F) The code compiles and prints "A,B".
4. Exhibit:
1 . import java.io.IOException;
2 . public class ExceptionTest(
3 . public static void main (String[]args)
4 . try (
5 . methodA();
6 .) catch (IOException e)(
7 . system.out.printIn("Caught IOException");
8 .) catch (Exception e)(
9 . system.out.printIn("Caught Exception");
1 0.)
1 1. )
1 2. public void methodA (){
1 3. throw new IOException ();
14.)
15. )
What is the result?
A) The program executes normally without printing a message.
B) The output is caught IOException.
C) The code will not compile.
D) The output is caught exception.
5. Exhibit:
1 . public class X implements Runnable (
2 .private int x;
3 .private int y;
4 .
5 .public static void main(String [] args) (
6 .X that = new X();
7 .(new Thread(that)) . start( );
8 .(new Thread(that)) . start( );
9 .)
1 0.
1 1. public synchronized void run( ) (
1 2.for (;;) (
1 3.x++;
1 4.y++;
1 5.System.out.printIn("x = " + x
1 6.)
1 7.)
1 8. )
What is the result?
+ ", y = " + y);
A) The program prints pairs of values for x and y that are always the same on the same line (forexample, "x=1, y=1". In addition, each value appears twice (for example, "x=1, y=1" followed by"x=1, y=1")
B) Errors at lines 7 and 8 cause compilation to fail.
C) The program prints pairs of values for x and y that might not always be the same on the same line(for example, "x=2, y=1")
D) An error at line 11 causes compilation to fail.
E) The program prints pairs of values for x and y that are always the same on the same line (forexample, "x=1, y=1". In addition, each value appears twice (for example, "x=1, y=1" followed by"x=2s, y=2")
Solutions:
| Question # 1 Answer: Only visible for members | Question # 2 Answer: B,D,E | Question # 3 Answer: E | Question # 4 Answer: C | Question # 5 Answer: E |
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